Mirror formula can also be written as:

\frac{1}{2 v} + \frac{1}{2 u} = \frac{1}{f}

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\frac{1}{v} + \frac{1}{u} = \frac{2}{R}

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\frac{1}{v} + \frac{2}{u} = \frac{1}{f}

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\frac{1}{2 v} + \frac{4}{u} = \frac{3}{R}

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Solution

The correct option is B $\frac{1}{v} + \frac{1}{u} = \frac{2}{R}$
Focal length, $f = \frac{R}{2}$ , where $R$ = radius of curvature
So, $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$ can be written as
$\Rightarrow \frac{1}{v} + \frac{1}{u} = \frac{2}{R}$

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Similar questions

\frac{1}{u} + \frac{1}{v} = \frac{1}{f}

\frac{1}{f} = \frac{1}{v} - \frac{1}{u}

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\frac{1}{u} + \frac{1}{v} = \frac{2}{R}

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