Mixing of 0.1 mol of NaOH and 0.1 mol of acetic acid in one litre of water results into
an alkaline solution
The weak acid and strong base will react completely and form 0.1 M CH3COONa, which will then undergo hydrolysis as:
CH3COONa(aq) + H2O(I) ↔ CH3COOH(aq) + OH(aq)−
There are OH− ions and hence b.