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Salt of Strong Acid and Weak Base

Mixing of 0.1...

Question

Mixing of 0.1 mol of NaOH and 0.1 mol of acetic acid in one litre of water results into

an acidic solution

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an alkaline solution

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a neutral solution

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a solution with no free ions

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Solution

The correct option is B
an alkaline solution

The weak acid and strong base will react completely and form 0.1 M $C H_{3} C O O N a$ , which will then undergo hydrolysis as:
$C H_{3} C O O N a (a q)$ + $H_{2} O (I)$ $\leftrightarrow$ $C H_{3} C O O H (a q)$ + ${O H (a q)}^{-}$

There are ${O H}^{-}$ ions and hence b.

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Similar questions

Mixing of 0.1 mol of NaOH and 0.1 mol of acetic acid in one litre of water results into

20 m L

0.1 N

10 m L

0.1 N

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{C H}_{3} C O O H = 1.8 \times 10^{- 5} .

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(K_{b} = 5 \times 10^{- 4})

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