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Concentration Terms - An Introduction (w/w etc)

Mixture of ...

Question

Mixture of $1$ mole of $N a_{2} C O_{3}$ and $2$ moles of $N a H C O_{3}$ forms $1$ mole of $C O_{2}$ on heating. Thus, percent yleld of $C O_{2}$ is :

A

25 %

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B

50 %

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C

75 %

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D

100 %

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Solution

The correct option is D $100 %$
The reaction is as follows:
$2 N a H C O_{3} (s) (h e a t) \to N a_{2} C O_{3} (s) + C O_{2} (g) + H_{2} O (g)$
$N a_{2} C O_{3}$ doesnot dissociate as it is thermally stable.
So, $2$ moles of bicarbonate should produce $1$ mole of $C O_{2}$ .
Therefore, $%$ yield of reaction is $1 \times \frac{100}{1} = 100 %$ .

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