Mixture of C 6 H 5 CHO and HCHO is treated with NaOH- then this reaction involves-A- Reduction of HCHOB- Oxidation of HCHOC- Oxidation of C 6 H 5 CHOD- Reduction and oxidation of C 6 H 5 CHO

The correct option is B Oxidation of HCHOC_6H_5CHO + HCHO → C_6H_5 CH_2 OH + HCOOH Thus HCHO is oxidised to HCOOH ...

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Oxidation and Reduction

Mixture of C ...

Question

Mixture of $C_{6} H_{5} C H O$ and HCHO is treated with NaOH, then this reaction involves:

Oxidation of HCHO

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Reduction of HCHO

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Oxidation of

C_{6} H_{5} C H O

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Reduction and oxidation of

C_{6} H_{5} C H O

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Solution

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A mixture of $C_{6} H_{5} C H O$ and $H C H O$ is treated with $N a O H$ , then the Cannizzaro’s reaction involves:

H C H O + 2 [A g (N H_{3})_{2}]^{+} + 3 O H^{-} \to 2 A g + H C O O^{-} + 4 N H_{3} + 2 H_{2} O

Identify the following reactions as oxidation or reduction reaction:
i) $K - e^{-} \to K^{+}$
ii) $F e^{3 +} + e^{-} \to F e^{2 +}$

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