wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Mixture of volatile components A and B has total vapour pressure (in torr):
p = 254 – 135 xA, where xA is the mole fraction of A in mixture hence poA and poB are (in torr)

A
254, 119
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
119, 254
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
135, 254
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
154, 119
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 119, 254
p = 254 – 135 xA
when A is pure xA = 1, So p = 254135=119 torr
when B is pure xA = 0, So p = 2540=254 torr

flag
Suggest Corrections
thumbs-up
46
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Liquids in Liquids and Raoult's Law
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon