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Question

Mixture X of 0.02 mole of [Co(NH3)4SO4]Br and 0.02 mole of [Co(NH3)5Br]SO4 was prepared in 2 litre of solution:

1 litre of mixture X + excess of AgNO3Y
1 litre of mixture X + excess of BaCl2Z
Number of moles of Y and Z respectively are :

A
0.01, 0.02
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B
0.02, 0.01
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C
0.01, 0.01
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D
0.02, 0.02
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Solution

The correct option is B 0.01, 0.01
1 L of the mixture contains 0.01 mole of [Co(NH3)4SO4]Br and 0.01 mole of [Co(NH3)5Br]SO4.
0.01 mole of [Co(NH3)4SO4]Br reacts with excess of silver nitrate to produce 0.01 mole of Y which is AgBr.
[Co(NH3)4SO4]Br0.01mole+AgNO3excess[Co(NH3)4SO4]NO3+AgBrY,0.01mole
0.01 mole of [Co(NH3)5Br]SO4 reacts with excess of BaCl2 to give 0.01 mole of Z which is BaSO4.
[Co(NH3)5Br]SO40.01mole+BaCl2excess[Co(NH3)5Br]Cl2+BaSO4Z,0.01mole

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