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Stoichiometric Calculations

Mn2+aq can be...

Question

$M n^{2 +} (a q)$ can be determined by titration with ${M n O_{4}}^{-} (a q)$ .
$M n^{2 +} + {M n O_{4}}^{-} + {O H}^{-} \to M n O_{2} + H_{2} O (unbalanced)$

A $25.0$ mL sample of $M n^{2 +}$ (aq) requires $34.77$ mL of $0.05876 M K M n O_{4}$ (aq) for its titration. The molarity of $M n^{2 +}$ is $y \times 10^{- 4} M$ , then y is ________.

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Solution

$M n^{2 +} (a q)$ can be determined by titration with ${M n O_{4}}^{-} (a q)$ .
$3 M n^{2 +} + {2 M n O_{4}}^{-} + {4 O H}^{-} \to 5 M n O_{2} + 2 H_{2} O (unbalanced)$
$3 m o l e s M n^{2 +} \equiv 2 m o l e s K M n O_{4}$
$3 \times 25.0 \times M_{1} = 2 \times 34.77 \times 0.05876$
Hence, $M_{1} = 0.05448 M = 544 \times 10^{- 4} M$
Therefore, the value of $y$ is $544$ .

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