${M n}^{2 +}$ can be converted to ${M n}^{7 +}$ by reacting with:

P b O_{2}

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S n {C l}_{2}

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{S O}_{2}

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{C l}_{2}

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Solution

The correct option is A $P b O_{2}$
$M n^{2 +}$ can be converted to $M n^{7 +}$ by reacting with $P b O_{2}$ .
$5 P b O_{2} brown + 2 M n (N O_{3})_{2} + 6 H N O_{3} \to 2 H M n O_{4} + 5 P b (N O_{3})_{2} + 2 H_{2} O$
In this reaction, $M n$ is oxidized and $P b$ is reduced.

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