$M n^{+ 3}$ ion loses 3 electrons, its oxidation number will be

0

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+ 3

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+ 6

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- 3

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Solution

The correct option is C $+ 6$
$M n^{3 +}$ $-$ $3$ $e^{-}$ $\to$ $M n^{6 +}$
Therefore, its oxidation state increases to $+ 6$ .

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