MN and RS are chord of a circle, which intersect at P outside the circle. If PN = 3cm, MN= 5 cm and PR = 2cm, then the value of SR is equal to

5 cm

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8 cm

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15 cm

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10 cm

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Solution

The correct option is D 10 cm

$P N \times P M = P R \times P S$
$(P M = P N + M N = 3 + 5 = 8)$
$3 \times 8 = 2 \times (2 + S R)$
$12 = 2 + S R$
$S R = 10$
Hence, the correct option is d.

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