MN, OP, and QR are three lines intersecting at the same point A, as shown in the figure below. Find the value of 5a, if x = 3a, y = 5x, and z = 6x.
A
5∘
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B
10∘
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C
12∘
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D
25∘
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Solution
The correct option is D25∘ The lines QR and MN are intersecting at point A. So, ∠QAN = ∠MAR = z [Vertically opposite angles]
Since, OP is a line, so, sum of all angles on the line is 180o. So, ∠MAO+∠MAR+∠RAP=180o Now, according to the question,
∠MAO+∠MAR+∠RAP=180o ⇒y+z+x=180o ⇒5x+6x+3a=180o [Given: y = 5x, z = 6x, and x = 3a] ⇒5(3a)+6(3a)+3a=180o ⇒15a+18a+3a=180o ⇒36a=180o ⇒a=5o Hence, 5a=5×5o=25o