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MnO2+4HClMnCl2+2H2O+Cl2
2 moles MnO2 reacts with 4 moles of HCl to form 11.2 L Cl2 at STP. Thus, percent yield of Cl2 is:

A
25%
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B
50%
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C
100%
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D
75%
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Solution

The correct option is B 50%
The reaction is as follows:
MnO2+4HClMnCl2+2H2O+Cl2
2 mol 4 mol (limiting reagent)
So, according to equation, 22.4 L of Cl2 should be formed but, only 11.2 L forms.
Therefore, % yield is 11.2×10022.4=50%.

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