MnO2 when fused with KOH and oxidized in air gives a dark green compound X. In acidic X. In acidic solution, X undergoes disproportion to give an intense purple compound Y and MnO2. The compounds X and Y respectively, are
2MnO2+4KOH+O2→2K2MnO4+2H2O3K2MnO4+4HCl→2KMnO4(purple)+MnO2+4KCl+2H2O