Mobilities of electrons and holes in a sample of intrinsic Ge at room temperature are $0.35 m^{2} / V - s$ and $0.18 m^{2} / V - s$ respectively. If the electron and hole densities are each equal to $2.5 \times 10^{19} / m^{3}$ , the Ge conductivity will be

3.12 S / m

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2.12 S / m

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1.12 S / m

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4.12 S / m

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Solution

The correct option is B $2.12 S / m$
Conductivity of Ge
$σ = e (n_{e} μ_{e} + n h μ_{h})$
Here $n_{e} = n_{h} = 2.5 \times 10^{19} m^{3}$
$e = 1.6 \times 10^{- 19}$
$(2.5 \times 10^{19} \times 0.35 + 2.5 \times 10^{19} \times 0.18)$
$= 1.6 \times 10^{- 19} \times 2.5 \times 10^{19} \times 0.53$
$= 2.12 S / m$

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