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Byju's Answer
Standard XII
Physics
Mixed Combination of Cells
Mobility of c...
Question
Mobility of charged particles is
6
×
10
−
2
m
2
V
−
1
s
−
1
.
If the electric field applied is
9
×
10
−
3
V/m
, then the drift speed would be
A
0.54
mm/s
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B
2
m/s
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C
0.69
×
10
−
4
m/s
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D
2
×
10
−
4
mm/s
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Solution
The correct option is
A
0.54
mm/s
Mobility
(
μ
)
is defined as,
μ
=
v
d
E
So,
v
d
=
μ
E
=
6
×
10
−
2
×
9
×
10
−
3
=
0.54
mm/s
Suggest Corrections
3
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