Mode=?
(a)xk+h.{(fk−1−fk)(2fk−fk−1−fk+1)} (b) xk+h.{(fk−fk−1)(2fk−fk−1−fk+1)}(c) xk+h.{(fk−fk−1)(fk−2fk−1−fk+1)} (d) xk+h.{(fk−fk−1)(fk−fk−1−2fk+1)}
Mode = (b) xk+h.{(fk−fk−1)(2fk−fk−1−fk+1)} ie. Option B is correct