Mode of the following data.
Interval 0-20 20-40 40-60 60-80 80-100
Frequency 6 8 12 10 6

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Solution

Here, maximum frequency is $12$ .
$∴$ Modal class $= 40 - 60$
So, $l = 40, f_{0} = 8, f_{1} = 12, f_{2} = 10$ and $h = 20$
$\Rightarrow$ $M o d e = l + \frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}} \times h$

$= 40 + \frac{12 - 8}{2 \times 12 - 8 - 10} \times 20$

$= 40 + \frac{4}{6} \times 20$

$= 40 + 13.33$

$= 53..33$

Suggest Corrections

Class-interval	0 - 20	20 - 40	40 - 60	60 - 80	80 - 100	100 - 120
Frequency	10	35	52	61	38	20

Marks	0 - 20	20 - 40	40 - 60	60 - 80	80 - 100
Frequency	5	10	20	10	15

Class Interval	0-10	10-20	20-30	30-40	40-50	50-60	60-70
Frequency	7	6	10	16	P	8	10

Class interval	0-10	10-20	20-30	30-40	40-50	50-60	60-70
Frequency	8	10	......	16	12	6	7

Life period (in hrs)	0-20	20-40	40-60	60-80	80-100	100-120
Frequency	100	35	52	61	38	29