Modulus of Elasticity is dimensionally equivalent to:

Stress

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Surface tension

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Strain

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Coefficient of viscosity

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Solution

The correct option is D Stress
Modulus of elasticity $= M^{1} L^{- 1} T^{- 2}$
Stress $= M^{1} L^{- 1} T^{- 2}$
Surface tension $= \frac{f}{l} = M^{1} L^{0} T^{- 2}$
Strain $= \frac{Δ L}{L} = M^{0} L^{0} T^{0}$
Coeff of viscosity $= F / A \frac{d v_{x}}{d x} = \frac{M L T^{- 2}}{L^{2} \frac{L T^{- 1}}{L}} = M L^{- 1} T^{- 1}$
Hence, option A is correct.

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