Mohan gets 3 marks for each correct sum and loses 2 marks for each wrong sum. He attempts 30 sums and obtains 40 marks. The number of sums solved correctly is
A
10
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B
15
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C
20
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D
25
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Solution
The correct option is C20 It is given that, Mohan gets 3 marks for each correct answer and loses 2 marks for each wrong answer.
He attempted 30 sums and got 40 marks.
Let the number of sums solved correctly be n. Then number of wrong sums =30−n ∴3n−2.(30−n)=40