wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Mohan was born on February 29 in the year 1960. How many birthdays will he celebrate upto February 1976?

A
16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 4
February 29 will come in every leap year.
1976 is also a leap year.

Mohan was born on February 29, 1960, which is also a leap year.

Total leap years till February 1976 are 4.
Therefore, he will celebrate his 4 birthdays till Feb 1976.

Hence, option C.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Counting Principle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon