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Total Surface Area of a Cuboid

Mohit painted...

Question

Mohit painted a closed box of length $2.5 m$ , breadth $2 m$ and height $1 m$ . How much surface area did he cover, if he painted all except the bottom of the box?

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Solution

Area = $2 h (l + b) + l b$
$= 2 (1) (4.5) + (2.5) (2)$
$= 9 + 5 = 14 m^{2}$ .

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