Mol- mass of acid - Equivalent - acidity

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Stoichiometric Calculations

Mol. mass of ...

Question

Mol. mass of acid = Equivalent $\times$ acidity

True

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False

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Solution

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Similar questions

K_{2} C r_{2} O_{7}

1 m o l

H_{2} S O_{4}

2 m o l

N a O H

1

H_{2} S O_{4}

1

N a O H

H_{2} S O_{4}

N a O H

The equivalent mass of $K M n O_{4}$ in acidic medium is (molar mass of $K M n O_{4}$ = 158 g/mol)

N_{2} H_{4}

I O_{3}^{-}

I^{+}

N_{2} H_{4} + I O_{3}^{-} + H^{+} ⟶ N_{2} + I^{+} + H_{2} O

N_{2} H_{4}

^{- 1}

a .

b .

H

(M w = 210 g m m o l^{- 1})

70 g m e q^{- 1}

N a O H

1 m o l

c .

C_{6} (C O O H)_{6}

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