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Sodium Thiosulphate

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Question

..............mol of $N_{2}$ are needed to produce 3.8 mol of $N H_{3}$ by reaction with hydrogen.

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Solution

$N_{2} + 3 H_{2} \to 2 N H_{3}$
$1 m o l e N_{2} \to 2 m o l e N H_{3}$
$\frac{1}{2} m o l e N_{2} \leftarrow 1 m o l e N H_{3}$
$\frac{3.8}{2} m o l e N_{2} \leftarrow 3.8 m o l e N H_{3}$
$1.9 m o l e N_{2} \leftarrow 3.8 m o l e N H_{3}$

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