Molal depression of freezing point of water is ${1.86}^{0} C$ per 1000 g of water. 0.02 mole of urea dissolved in 100 g of water will produce a lowering of the freezing temperature by :

{0.186}^{0} C

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{0.372}^{0} C

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{1.86}^{0} C

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{3.72}^{0} C

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Solution

The correct option is B ${0.372}^{0} C$
$Δ T_{f} = K_{f} m$
$Δ T_{f} = 1 \cdot 86 \times \frac{0 \cdot 02}{100} \times 1000$
$Δ T_{f} = 0 \cdot 372^{0} C$
So, lowering of freezing temperature $= 0 \cdot 372^{0} C$

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