Molality of a solution in which 0.13 mole of solute is dissolved in 500 gm of water.

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1.3

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2.6

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0.26

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Solution

The correct option is D 0.26
We know,
Molality $m = \frac{N u m b e r o f g r a m m o l e s o f s o l u t e}{M a s s o f s o l v e n t (k g)}$

Mass of solvent i.e water is given to be 500 gm
Gram moles of solute is 0.13

$∴ M o l a l i t y = \frac{0.13}{500 \times 10^{- 3}}$ (Converting gram to kg)
= 0.26

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