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Question

Molar heat capacity of an ideal gas at constant volume is given by Cv=16.5+102T(in Joule). If 3.5 moles of this ideal gas are heated at constant volume from 300K to 400K the change in internal energy (in kJ) will be:

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Solution

In integral form, dU=nT2T1CvdT

ΔU=nT2T1(16.5+0.01T)dT=n400300(16.5+0.01T)dT
After integration, ΔU=7000J=7kJ
Hence, the correct answer is 7kJ.

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