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Byju's Answer
Standard XII
Physics
RMS and KE Expressions
Molar heat ca...
Question
Molar heat capacity of an ideal gas at constant volume is given by
C
v
=
16.5
+
10
−
2
T
(in Joule). If 3.5 moles of this ideal gas are heated at constant volume from 300K to 400K the change in internal energy (in kJ) will be:
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Solution
In integral form,
∫
d
U
=
n
∫
T
2
T
1
C
v
d
T
Δ
U
=
n
∫
T
2
T
1
(
16.5
+
0.01
T
)
d
T
=
n
∫
400
300
(
16.5
+
0.01
T
)
d
T
After integration,
Δ
U
=
7000
J
=
7
k
J
Hence, the correct answer is
7
k
J
.
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