Question

Molarity of a solution that has $3.42g$ sucrose in $500mL$ solution is.

• A. 0.2
• B. 0.02
• C. 2
• D. 0.342

Answer 1

The correct option is B 0.02

We know that,
Molarity=$\frac{\text{No. of moles of solute}}{\text{No of litres of solution}}$
We know the given weight of sucrose from which the number of moles of sucrose can be calculated.
$\therefore$ No. of moles =$\frac{Givenweight}{Molecularweight}$(solute is sucrose)
$=\frac{3.42}{342}=0.01$
When 0.01 moles of sucrose is added to $500mL$,
$\Rightarrow Molarity=0.01\times \frac{1}{500\times {10}^{-3}}(1mL={10}^{-3}L)$
$\Rightarrow$ Molarity = 0.02 M