Question

Molarity of $H_{2}S{O}_4$ is 18M. Its density is 1.8 g/ml. Hence molality is

• A. 36
• B. 200
• C. 500
• D. 18

Answer 1

The correct option is C 500

$m=\frac{M}{d-\left(\frac{M\times GMw}{1000}\right)}=\frac{1}{1.8-\left(\frac{18\times 98}{1000}\right)}=500$