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Question

Molarity of solution containing 12.6 grams of oxalic acid in 100 ml of the solution is:

A
0.75 M
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B
0.5 M
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C
1.0 M
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D
2 M
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Solution

The correct option is D 1.0 M
Molar mass of Oxalic acid (H2C2O4.2H2O)=126

Molarity=(Mass of solute in gramsMolar mass)×1000Volume of the solution in mL

Molarity=(12.6126)×1000100

Molarity=1 M

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