Molarity of solution containing $12.6$ grams of oxalic acid in $100 m l$ of the solution is:

0.75 M

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0.5 M

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1.0 M

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2 M

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Solution

The correct option is D $1.0 M$
Molar mass of Oxalic acid $(H_{2} C_{2} O_{4} .2 H_{2} O) = 126$

$M o l a r i t y = \frac{(\frac{M a s s o f s o l u t e i n g r a m s}{M o l a r m a s s}) \times 1000}{V o l u m e o f t h e s o l u t i o n i n m L}$

$M o l a r i t y = \frac{(\frac{12.6}{126}) \times 1000}{100}$

$M o l a r i t y = 1 M$

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Molarity of solution containing 12.6 grams of oxalic acid in 100 ml of the solution is:

The correct option is D 1.0 MMolar mass of Oxalic acid (H2C2O4.2H2O)=126Molarity=(Mass of solute in gramsMolar mass)×1000Volume of the solution in mLMolarity=(12.6126)×1000100Molarity=1 M

Molarity of solution containing $12.6$ grams of oxalic acid in $100 m l$ of the solution is: