Mole fraction of A in H 2 O is 0-2- The molality of A in H 2 O isA- 13-8B- 15-5C- 14-5D- 16-8

The correct option is A 13.8 nA/nA+H_2O = 0.2 ⟹0.8n_4 = 0.2n_(H_2O) 4n_A =n_(H_2O) n_A =n_(H_2O)/4 n_A =n_(H_2O)/4 =1000/18 n_(H_2O) in 1000gm of it = 1000/18 ...

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Byju's Answer

Standard XII

Chemistry

Molality

Mole fraction...

Question

Mole fraction of A in $H_{2} O$ is 0.2. The molality of A in $H_{2} O$ is

13.8

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15.5

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14.5

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16.8

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Solution

The correct option is A
13.8

$\frac{n A}{n A + H_{2} O}$ = 0.2

$⟹$ 0.8 $n_{4}$ = 0.2 $n_{(} H_{2} O)$

4 $n_{A}$ = $n_{(} H_{2} O)$

$n_{A}$ = $\frac{n_{(H_{2} O)}}{4}$

$n_{A}$ = $\frac{n_{(H_{2} O)}}{4}$ = $\frac{1000}{18}$

$n_{(} H_{2} O)$ in 1000gm of it = $\frac{1000}{18}$

$n_{A}$ = $\frac{n_{(H_{2} O)}}{4}$ = $\frac{1000}{18}$ = $\frac{250}{18}$ = 13.8

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Mole fraction of A in H2O is 0.2. The molality of A in H2O is

The correct option is A 13.8 nAnA+H2O = 0.2 ⟹0.8n4 = 0.2n(H2O) 4nA =n(H2O) nA =n(H2O)4 nA =n(H2O)4 =100018 n(H2O) in 1000gm of it = 100018 nA =n(H2O)4 = 100018= 25018 = 13.8

Mole fraction of A in $H_{2} O$ is 0.2. The molality of A in $H_{2} O$ is