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Question

Mole fraction of glycerine (C3H5(OH)3) in a solution of 36 g of water and 46 g of glycerine is :

A
0.46
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B
0.36
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C
0.20
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D
0.40
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Solution

The correct option is D 0.20
No. of moles of glycerine = 46/92 (where 92 is M.M. of glycerine)
= 0.5moles

No. of moles of water = 36/18 (where 18 is M.M. of water)
= 2moles

So, mole fraction oh glycerine = 0.5/2.5
= 1/5
= 0.20

Hence the correct option is C.

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