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Byju's Answer
Standard XII
Chemistry
Percentage Composition
Mole fraction...
Question
Mole fraction of glycerine
(
C
3
H
5
(
O
H
)
3
)
in a solution of 36 g of water and 46 g of glycerine is :
A
0.46
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B
0.36
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C
0.20
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D
0.40
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Solution
The correct option is
D
0.20
No. of moles of glycerine = 46/92 (where 92 is M.M. of glycerine)
= 0.5moles
No. of moles of water = 36/18 (where 18 is M.M. of water)
= 2moles
So, mole fraction oh glycerine = 0.5/2.5
= 1/5
= 0.20
Hence the correct option is C.
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