Question

Mole fraction of helium in a saturated solution at ${\text{20}}^{\circ }\text{C}$ is $1.2\times {10}^{-6}$. Find out the pressure of helium above the solution. Given that at ${20}^{\circ }\text{C}$, Henry's Law Constant $\left(k_H\right)$ = 144.97 k bar.

Answer 1

$P=K_{H}C$ $K_H=144.97kbar$

$=14.97\times {10}^4\times 1.2\times {10}^{-6}$ $=14.97\times {10}^{4}atm$

$=18.86\times {10}^{-2}atm$

So, pressure of the above solution= $18.86\times {10}^{-2}atm$