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Stoichiometry

Mole fraction...

Question

Mole fraction of $I_{2}$ in $C_{6} H_{6}$ is 0.2. The molality of $I_{2}$ in $C_{6} H_{6}$ is:

3.2

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6.40

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1.6

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4.3

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Solution

The correct option is D $3.2$
Let the solution be $x$ molal.
Moles of benzene present in 1000g of benzene $= \frac{1000}{78} = 120.82$ .
Mole fraction of solute $= \frac{x}{x + 12.82}$

$= 0.2 =$ $\frac{x}{x + 12.82}$ .

On solving for $x$ we get $x = 3.2$

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