Mole fraction of I2 in benzene is 0.2. Calculate the molality of I2 in solution.

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Solution

$T h e m i x t u r e c o n t a i n s 0.2 m o l e s o f i o d i n e a n d 0.8 m o l e s o f b e n z e n e . 0.8 m o l e s o f b e n z e n e = 0.8 \times m o l a r m a s s o f b e n z e n e = 0.8 \times 78 = 62.4 g M o l a l i t y = \frac{N o o f m o l e s o f s o l u t e}{W e i g h t o f t h e s o l v e n t i n K g} = \frac{0.2}{62.4 \times 10^{- 3}} = 3.205 m o l a l$

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