Question

Mole fraction of solute present in an aqueous solution having molality equal to $2$ is:

• A. $0.9653$
• B. $0.347$
• C. $0.653$
• D. $0.0347$

Answer 1

The correct option is D $0.0347$

Mole fraction (x) : The ratio of number of moles of the solute or solvent present in the solution and the total number of moles present in the solution is known as the mole fraction of substances concerned.
Mole fraction of solute =$\frac{n}{n+N}=\frac{2}{2+\frac{1000}{18}}=\frac{2}{2+55.5}=0.0347$