Mole fractions of A and B in a mixture in which 6-023 - 1023 molecules of A and 10-4 - 1023 molecules of B are present are-

To find mole fraction, we need number of moles. N_A = Number of moles of A = 6.023× 10^23/6.023× 19^23=1 N_B = Number of moles of B = 10.4× 10^23/6.023× 10^23 ...

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Mole fraction...

Question

Mole fractions of A and B in a mixture in which $6.023 \times 10^{23}$ molecules of A and $10.4 \times 10^{23}$ molecules of B are present are:

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Solution

To find mole fraction, we need number of moles.

$N_{A}$ = Number of moles of A = $\frac{6.023 \times 10^{23}}{6.023 \times 19^{23}} = 1$

$N_{B}$ = Number of moles of B = $\frac{10.4 \times 10^{23}}{6.023 \times 10^{23}} = 1.73$

$X_{A} = \frac{N_{A}}{N_{A} + N_{R}} = \frac{1}{2.73} = 0.37$

$X_{B} = \frac{N_{B}}{N_{A} + N_{R}} = \frac{1.73}{2.73} = 0.63$

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Mole fractions of A and B in a mixture in which 6.023×1023 molecules of A and 10.4×1023 molecules of B are present are:

To find mole fraction, we need number of moles. NA = Number of moles of A = 6.023×10236.023×1923=1 NB = Number of moles of B = 10.4×10236.023×1023=1.73 XA=NANA+NR=12.73=0.37 XB=NBNA+NR=1.732.73=0.63

Mole fractions of A and B in a mixture in which $6.023 \times 10^{23}$ molecules of A and $10.4 \times 10^{23}$ molecules of B are present are: