___ mole/s of oxygen atoms are present in 36 gms water.

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Solution

$M o l e s o f W a t e r = \frac{G i v e n m a s s}{M o l a r m a s s}$

$= \frac{36}{18} = 2$

1 molecule of $H_{2}$ O contains 1 molecule of oxygen and 2 molecules of hydrogen.

So, number of oxygen atoms = 2 moles

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___ mole/s of oxygen atoms are present in 36 gms water.

MolesofWater=GivenmassMolarmass =3618=2 1 molecule of H2O contains 1 molecule of oxygen and 2 molecules of hydrogen. So, number of oxygen atoms = 2 moles

$M o l e s o f W a t e r = \frac{G i v e n m a s s}{M o l a r m a s s}$

$= \frac{36}{18} = 2$

1 molecule of $H_{2}$ O contains 1 molecule of oxygen and 2 molecules of hydrogen.

So, number of oxygen atoms = 2 moles