Molecular formula of oxygen is $O_{2}$ while sulphur is $S_{8}$ , why?

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Solution

Due to small size $p π - p π$ bond is stable.
∴ $O = O$ is formed.
Also $S - S$ Bond energy > $O - O$ Bond energy
∴ S-S is more stable and catenation tendency of sulphur is more.

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Similar questions

Q. (a) Define gram molecular mass of a substance. How much is the gram molecular mass of oxygen ?
(b) If sulphur exists as S₈ molecules, calculate the number of moles in 100 g of sulphur. (S = 32 u)

Q. (i) The acidic character of hydrides of group 15 increases from

H_{2} O

H_{2} T e

. Why ?
(iI) Dioxygen is a gas while sulphur

(S_{8})

is a solid. Why?

The molecular formula for eelemental sulphur si $S_{8}$ . In a sample of 5.12 g of slphur:
(a) how many moles of sulphur are present ?
(b) HOw many molecules and atoms are present?

Q. Assertion: Both rhombic and monoclinic sulphur exist as

S_{8}

but oxygen exists as

O_{2} .

Reason: Oxygen form

p π - p π

multiple bond due to small size and small bond length but

p π - p π

bonding is not possible in sulphur due to its larger atomic size than oxygen.

Q. Write the formula of the compound of sulphur which is obtained when

c o n c . H N O_{3}

oxidises

S_{8}

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Molecular formula of oxygen is O2 while sulphur is S8, why?

Due to small size pπ−pπ bond is stable.∴O=O is formed.Also S−S Bond energy > O−O Bond energy∴ S-S is more stable and catenation tendency of sulphur is more.

Molecular formula of oxygen is $O_{2}$ while sulphur is $S_{8}$ , why?

Due to small size $p π - p π$ bond is stable.
∴ $O = O$ is formed.
Also $S - S$ Bond energy > $O - O$ Bond energy
∴ S-S is more stable and catenation tendency of sulphur is more.