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Huckel's Rule of Aromaticity

Molecular for...

Question

Molecular formula of some compounds are given in the box.
$C_{2} H_{4}$ , $C_{6} H_{14}$ , $C H_{3} - C H_{2} - C l$ , $C H_{3} - C O O H$ , $C_{6} H_{6}$

Which can be prepared by substitution reaction?

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Solution

$C H_{3} C H_{2} C l$ is prepared by substitution reaction.

A) $C H_{3} C H_{3} + C l_{2} s u n l i g h t - ---- \to C H_{3} C H_{2} C l$

H is replaced by chlorine, hence reaction is known as substitution reaction.

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Similar questions

C_{2} H_{4}

C_{6} H_{14}

C H_{3} - C H_{2} - C l

C H_{3} - C O O H

C_{6} H_{6}

C_{2} H_{4}

C_{6} H_{14}

C H_{3} - C H_{2} - C l

C H_{3} - C O O H

C_{6} H_{6}

C H_{3} - C H_{2} - C O O - C H_{3}

C H_{3} - C H_{2} - C O O H

C H_{3} - C H_{2} - C O - C H_{3}

C H_{3} - O H

C H_{3} - C H_{2} - C H_{2} O H

C H_{3} - C O O H

C H_{3} - C O O - C H_{2} - C H_{2} - C H_{3}

C H_{2} = C H_{2} H C l \to C H_{3} - C H_{2} . C l

n C H_{2} = C H_{2} \to (C H_{2} - C H_{3})_{n}

C H_{3} - C O O H + C H_{3} - C H_{2} - O H \to C H_{3} - C O O C H_{2} C H_{3} + H_{2} O

S_{N} 2

C H_{3} - C l

C H_{3} - C | | O - C H_{2} - C l

C H_{3} - C H | C H_{3} - C H_{3} - C l

C H_{3} - C H_{2} - C l

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