Molecular mass of nitric acid is:

22 u

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12 u

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33 u

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63 u

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Solution

The correct option is D $63 u$
Molecular mass of nitric acid $(H N O_{3})$ $= (1 \times a t o m i c m a s s o f H) + (1 \times a t o m i c m a s s o f N) + (3 \times a t o m i c m a s s o f O)$
$= 1 \times (1 u) + 1 \times (14 u) + 3 \times (16 u)$
$= 63 u$

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