Molecular nitrogen can be converted into NO by the following reaction sequence, N2+3H2→2NH3 4NH3+5O2→4NO+6H2O Calculate the mass of NO formed from 100 g of N2 with excess of H2 and O2?
A
100 gm
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B
150.60 gm
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C
214.28 gm
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D
256.32 gm
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Solution
The correct option is C 214.28 gm N2+3H2→2NH3mole=1002810028×2 4NH3+5O2→4NO+6H2O 4 moles NH3 gives 4 moles of NO 20028 moles NH3 gives 4 moles of 20028 moles of NO Moles of NO formed from 100 g N2=20028 mass of NO formed =20028×30 gm = 214.28 gm