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Question

Molecular orbital theory for N2-

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Solution

N2−

The electronic configuration is KK (σ(2s))2 (σ∗(2s))2 (π(2px))2 (π(2py))2 (σ(2pz))2 (π∗(2px))1

Nb= 8 , Na =3

Bond Order= 2.5

It has one unpaired electron , therefore it is paramagnetic in nature.

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