Molecular weight of dibasic acid is W. Its equivalent weight will be :

\frac{W}{2}

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\frac{W}{3}

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W

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3 W

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Solution

The correct option is B $\frac{W}{2}$
Given,
Dibasic acid molecular weight $= W$
Dibasic acid $\Rightarrow$ Basicity $= 2$
$[∵ 2$ replaceable $H^{+}$ ions $]$

We know,
Equivalent weight $= \frac{M o l e c u l a r w e i g h t}{B a s i c i t y}$

$[∵ A c i d - b a s e r e a c t i o n s]$

$\Rightarrow$ Equivalent weight $= \frac{W}{2}$

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Molecular weight of dibasic acid is W. Its equivalent weight will be :

The correct option is B W2Given,Dibasic acid molecular weight =WDibasic acid ⇒ Basicity =2[∵2 replaceable H+ ions]We know,Equivalent weight =MolecularweightBasicity[∵Acid−basereactions]⇒ Equivalent weight =W2