Molecular weight of sulphuric acid is $X$ . Equivalent weight of orthophosphoric acid is:

X

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2 X

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\frac{X}{3}

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\frac{X}{4}

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Solution

The correct option is C $\frac{X}{3}$
The molecular weight of sulphuric acid $(H_{2} S O_{4})$ is equal to the molecular weight of $H_{3} P O_{4}$ .

But, acidity of $H_{3} P O_{4}$ is 3.

Therefore, Equivalent weight is $\frac{X}{3}$ .

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