Question

Molecule AB has a bond length of 1.617$\mathring{A}$ and a dipole moment of 0.38 D. The fractional charges on each atom (absolute magnitude) is :

$(e_0=4.802\times {10}^{-10}esu)$

• A. $0.5$
• B. $0.05$
• C. $0$
• D. $1.0$

Answer 1

The correct option is B $0.05$

Dipole moment $\left(\mu \right)=$ Electronic charge $\left(e\right)\times$ Distance $\left(d\right)$ .

$0.38D=0.38\times {10}^{-18}esu.cm=e\times 1.617\times {10}^{-8}cm$

$e=0.235\times {10}^{-10}esu$
Fraction charge $=\frac{0.235\times {10}^{-10}esu}{4.802\times {10}^{-10}esu}=0.05$

Thus, the fractional charges on each atom (absolute magnitude) is $0.05$.