moles of nitric acid are required to convert $1 m o l$ of phosphorus to _?

10,

phosphine

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4,

phosphoric acid

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48,

phosphorus acid

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20,

phosphoric acid

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Solution

The correct option is D $20,$ phosphoric acid
$1 m o l$ of phosphorus $(P_{4})$ requires $20 m o l$ of concentrated nitric acid $(H N O_{3})$ to produce $4 m o l$ of phosphoric acid $(H_{3} P O_{4})$ . The reaction is: $P_{4} + 20 H N O_{3} \to 4 H_{3} P O_{4} + 20 N O_{2} + 2 H_{2} O$

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Similar questions

Q. How many moles of nitric acid are required to convert

1 m o l

of sulfur to sulfuric acid?

Concentrated nitric acid oxidises phosphorus to phosphoric acid according to the following equation:
$P + 5 H N O_{3} \to H_{3} P O_{4} + 5 N O_{2} + H_{2} O$
If 6.2 g of phosphorus was used in the reaction, calculate:

(a) The number of moles of phosphorus taken and mass of phosphoric acid formed.
(b) Mass of nitric acid consumed at the same time.
(c) The volume of steam produced at the same time if measured at 760 mm Hg pressure and $273^{\circ} C .$