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Mole Fraction

Moles present...

Question

Moles present in 20 gm of water will be-

A

1.1

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B

1.11

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C

1.12

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D

1.13

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Solution

The correct option is B 1.11
Number of moles $= \frac{w e i g h t o f c o m p o u n d i n g r a m s}{M o l e c u l a r m a s s}$

Molecular mass of $H_{2} O = 18 g m o l e^{- 1}$
$N u m b e r o f m o l e s o f w a t e r = = \frac{20 g}{18 g m o l^{- 1}} = 1.11 m o l e$

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