Moment of force is given by

Force

\times

Perpendicular distance of the force from the pivot

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Force

\times

Perpendicular distance of the force from the centre of the object

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Force + Perpendicular distance of the force from the pivot

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Force + Perpendicular distance of the force from the centre of the object

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Solution

The correct option is A Force $\times$ Perpendicular distance of the force from the pivot
Torque or moment of force is the product of force and the perpendicular distance of the force from the pivot. It causes turning or rotation of bodies.

Torque = Force $\times$ Perpendicular distance of the force from the pivot

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Similar questions

The moment of a force about a given axis depends:

(a) only on the magnitude of force

(b) Only on the perpendicular distance of force from the axis

(d) both, on the force and its perpendicular distance from the axis.

A rod is pivoted at a point. A force of $20 N$ is applied at a distance of $20 c m$ from the pivot perpendicular to the rod as shown in the figure below. Calculate the moment of force about the pivot.

The moment of a force of 25 N about a point is 2.5 N m. Find the perpendicular distance of force from that point.

Q. A body is pivoted at a point. A force of

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is applied at a distance of

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from the pivot. Calculate the moment of force.

A body is pivoted at a point. A force of $20 N$ is applied at a distance of $20 c m$ from the pivot. Calculate the moment of force about the pivot.

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