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Question

Moment of inertia of a body about an axis is 4kgm2. The body is initially at rest and a torque of 8 Nm starts acting on it along the same axis. Work done by the torque in 20 s, in joules, is :

A
40
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B
640
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C
2560
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D
3200
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Solution

The correct option is D 3200
Angular acceleration of the body will be α=84=2 rad/s2.

Angular velocity in 20s will be ω=2(20)=40 rad/s.

Since by work energy theorem, work done is equal to the change in kinetic energy,

W=124(402)0=3200 J.



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